GCSE Mathematics (9-1)

Chapter 9: Review

The chapter problem, solved

Let hh be the number of hours. The first hall costs 18+6h18+6h pounds; the second costs 10+8h10+8h pounds.

Set the costs equal: 18+6h=10+8h18+6h=10+8h.

Subtract 1010 and 6h6h: 8=2h8=2h.

Divide by 22: h=4h=4.

At four hours, both halls cost £42. The equal point is after two hours, as you predicted or revised in the opener.

Mixed practice: choose a method and explain why

For each item, name the method before you work. After calculating, say why that method fits.

  1. Solve 5x−7=185x-7=18.
  2. Solve 4x+3=2x+154x+3=2x+15.
  3. A rectangle has length x+5x+5 and width xx. Its perimeter is 46 cm. Find its sides.
  4. Write and solve an inequality for values no greater than 6.
  5. Solve 3−2x<113-2x<11.
  1. Solve (x+1)(x−4)≥0(x+1)(x-4)\geq0.
  2. Solve x2−2x−8<0x^2-2x-8<0.
  1. Chapter 1 link: estimate 19.8×4.919.8\times4.9 and explain how the estimate checks an exact answer.
Answers
  1. Inverse operations: x=5x=5.
  2. Collect unknown terms: x=6x=6.
  3. 2(x+5)+2x=462(x+5)+2x=46, so x=9x=9; width 9 cm and length 14 cm.
  4. x≤6x\leq6.
  5. Subtract 3: −2x<8-2x<8; divide by −2-2 and reverse: x>−4x>-4.
  1. Roots −1,4-1,4; test intervals: x≤−1x\leq-1 or x≥4x\geq4.
  2. Factor: (x−4)(x+2)<0(x-4)(x+2)<0, so −2<x<4-2<x<4.
  3. Estimate 20×5=10020\times5=100. The exact product is 97.0297.02, which is close to the estimate.

What you can now do

Your relevance reflection

Return to your example of comparing costs. Write the equation that models it, then explain what its solution means. What other situation could use the same method?

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