GCSE Mathematics (9-1)

12.2 Factorising harder quadratics — Learn

Prerequisites: expanding brackets and factorising monic quadratics.

Objectives: factorise ax2+bx+cax^2+bx+c when aa is not 11, including cases where the leading coefficient is negative. This extends A4.

Split the middle term

For ax2+bx+cax^2+bx+c, find two numbers with product acac and sum bb. Split bxbx, then factor by grouping.

Example 1. Factorise 6x2+11x+36x^2+11x+3.

The product acac is 1818. The numbers 99 and 22 have product 1818 and sum 1111.

6x2+11x+3=6x2+9x+2x+36x^2+11x+3=6x^2+9x+2x+3 =3x(2x+3)+1(2x+3)=3x(2x+3)+1(2x+3) =(3x+1)(2x+3)=(3x+1)(2x+3)

Negative leading coefficient

Take out a negative factor first. Then use the same method.

Example 2. Factorise −2x2+5x+3-2x^2+5x+3.

$$ -2x^2+5x+3=-(2x^2-5x-3) $$ The product is −6-6 and the sum is −5-5, so use −6-6 and 11.

=−(2x2−6x+x−3)=-(2x^2-6x+x-3) =−(2x(x−3)+1(x−3))=-(2x(x-3)+1(x-3)) =−(2x+1)(x−3)=-(2x+1)(x-3)

Watch out. Choosing numbers with the right product is not enough. Their sum must match the middle coefficient too. Expand your final factors to check both.

You should now be able to

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