GCSE Mathematics (9-1)

12.5 The quadratic formula — Learn

Prerequisites: rearranging equations, square roots, and substituting values into a formula.

Objectives: solve a quadratic equation using the quadratic formula and interpret its discriminant. This covers A18 at Higher level.

The formula

For ax2+bx+c=0ax^2+bx+c=0, where a≠0a\ne 0,

x=−b±b2−4ac2ax= \frac{-b\pm\sqrt{b^2-4ac}}{2a}

The expression b2−4acb^2-4ac is the discriminant. A positive discriminant gives two real roots, zero gives one repeated root, and a negative discriminant gives no real roots.

Example 1. Solve 2x2+3x−2=02x^2+3x-2=0.

Here a=2a=2, b=3b=3, and c=−2c=-2.

x=−3±32−4(2)(−2)2(2)x= \frac{-3\pm\sqrt{3^2-4(2)(-2)}}{2(2)} =−3±254= \frac{-3\pm\sqrt{25}}{4} x=12orx=−2x= \frac{1}{2}\quad\text{or}\quad x=-2

Watch out. Keep the negative sign in c=−2c=-2 when substituting. The discriminant is 9−4(2)(−2)=259-4(2)(-2)=25, not 9−169-16.

You should now be able to

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