21.4 Proof of circle theorems — Practise
Work independently. Questions become more demanding as you progress. Check your answers after you have attempted the set.
- H A triangle stands on a diameter. State the angle at the circumference and the theorem that proves it.
- H A perpendicular from the centre meets a chord of length cm. State the two equal lengths.
- H One angle in a cyclic quadrilateral is . Find its opposite angle and name the reason.
- H A radius meets a tangent at . State the angle and the theorem.
- H Two angles stand on the same chord in the same segment. One is . State the other angle and reason.
- H Two tangents from have lengths and . Find , stating the theorem used.
- H An angle in a semicircle is . The triangle has another angle of . Find the last angle and give both reasons used.
- H A tangent-chord angle is degrees. The alternate segment angle is . Find and name the theorem.
- H Opposite angles of a cyclic quadrilateral are and . Find and both angles.
- H A perpendicular from centre bisects chord . If and , find .
Answers and concise solutions
1. State the result and reason
Answer: , by the angle in a semicircle theorem.
2. State the chord result
Answer: Each half is cm, because the perpendicular from the centre bisects the chord.
3. Use a theorem in a proof
Answer: , since opposite angles in a cyclic quadrilateral total .
4. State the tangent result
Answer: , because the tangent is perpendicular to the radius at the point of contact.
5. Same segment reasoning
Answer: , because angles in the same segment are equal.
6. Use equal tangent lengths
Answer: , since tangents from the same external point are equal.
7. Complete the proof
Answer: , using the angle in a semicircle theorem and the triangle angle sum.
8. Apply the alternate segment theorem
Answer: , by the alternate segment theorem.
9. Prove by setting opposite angles
Answer: ; the angles are and .
10. Use the chord theorem
Answer: , since the perpendicular from the centre bisects the chord.