GCSE Mathematics (9-1)

4.6 Fractions and percentages as operators — Practise

  1. Work out 38\frac{3}{8} of £64£64.
  2. Work out 15%15\% of 8080.
  3. A £60 coat is reduced by 20%20\%. Work out its sale price.
  4. After a 25%25\% increase, a price is £90. Work out the original price.
  5. Write 320\frac{3}{20} as a percentage, then work out 320\frac{3}{20} of £140.
  6. Increase £80 by 15\frac{1}{5}. Work out the new price.
  7. After a 10%10\% decrease, a price is £54. Work out the original price.
Answers and concise solutions

1. Answer 1

Answer: 38×64=24\frac{3}{8}\times64=24, so the amount is £24.

2. Answer 2

Answer: 15%×80=15100×80=12.15\%\times80=\frac{15}{100}\times80=12.

3. Answer 3

Answer: 20%20\% of £60 is £12, so £60-£12=£48.

4. Answer 4

Answer: The new price is 125%125\% of the original. £90 divided by 1.251.25 is £72.

5. Answer 5

Answer: 320=15%\frac{3}{20}=15\%. Also 320×140=£21\frac{3}{20}\times140=£21.

6. Increase by one fifth

Answer: 15=20%\frac{1}{5}=20\%. The multiplier is 1.21.2, so £80×1.2=£96£80\times1.2=£96.

7. Original price after decrease

Answer: The sale price is 90%90\% of the original. £54÷0.9=£60£54\div0.9=£60.

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