GCSE Mathematics (9-1)

3.2 Estimating powers and roots — Learn

Prerequisites: square and cube numbers, place value and rounding.

Objectives: estimate powers and roots; give a reason for an estimate by comparing nearby values.

By the end of this section, you can estimate powers and roots and explain why your estimate is reasonable.

This section covers N6.

Compare with known values

To estimate a root, find two nearby powers you know. The root lies between the matching base values. You can then refine the estimate.

Example 1. Estimate 70\sqrt{70} to the nearest whole number.

82=6492=818^2=64 \qquad 9^2=81

So 70\sqrt{70} lies between 8 and 9. The midpoint of 64 and 81 is 72.5. Since 70<72.570<72.5, 70\sqrt{70} rounds to 8.

Example 2. Estimate 2003\sqrt[3]{200} to the nearest whole number.

53=12563=2165^3=125 \qquad 6^3=216

So 2003\sqrt[3]{200} lies between 5 and 6. The midpoint of 125 and 216 is 170.5. Since 200>170.5200>170.5, 2003\sqrt[3]{200} rounds to 6.

Estimating powers

You can estimate a power by rounding its base first. State the rounded base and then calculate its power.

Example 3. Estimate 19319^3 by rounding 19 to one significant figure.

19≈2019\approx20 193≈20319^3\approx20^3 203=800020^3=8000

The estimate is 8000. The exact value is 193=685919^3=6859, so rounding the base gives an estimate that is 1141 too high.

Watch out. A nearby number can give a poor estimate when the power grows quickly. Rounding 19 to 20 changes the cube from 68596859 to 80008000. State the estimate method and check that its accuracy suits the question.

Progress check

After 20 doublings, the file size is 2202^{20}. Since 210=10242^{10}=1024, predict whether it is closer to 10310^3 or 10610^6 units. The next section gives a way to rewrite the power.

You should now be able to

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