GCSE Mathematics (9-1)

22.3 Vectors in geometric problems and proofs — Practise with help

Warm-up: remember

  1. Work out (2−1)+(−34)\begin{pmatrix}2\\-1\end{pmatrix}+\begin{pmatrix}-3\\4\end{pmatrix}.
  2. What vector reverses (5−2)\begin{pmatrix}5\\-2\end{pmatrix}?
Answers and feedback
  1. (−13)\begin{pmatrix}-1\\3\end{pmatrix}; add matching components.
  2. (−52)\begin{pmatrix}-5\\2\end{pmatrix}; reversing a vector changes both signs.

Practise with help

1. In triangle PQRPQR, PQ→=a\overrightarrow{PQ}=\mathbf{a} and QR→=b\overrightarrow{QR}=\mathbf{b}. Find PR→\overrightarrow{PR}.

Hint

Follow the route from PP to QQ to RR.

Next step

PR→=PQ→+QR→\overrightarrow{PR}=\overrightarrow{PQ}+\overrightarrow{QR}.

Full working

PR→=a+b\overrightarrow{PR}=\mathbf{a}+\mathbf{b}.

2. In parallelogram ABCDABCD, AB→=u\overrightarrow{AB}=\mathbf{u} and AD→=v\overrightarrow{AD}=\mathbf{v}. Find AC→\overrightarrow{AC}.

Hint

Use the route AA to BB to CC.

Next step

BC→=AD→=v\overrightarrow{BC}=\overrightarrow{AD}=\mathbf{v}.

Full working

AC→=AB→+BC→=u+v\overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC}=\mathbf{u}+\mathbf{v}.

3. In the same parallelogram, find DB→\overrightarrow{DB}.

Hint

Use the route DD to AA to BB.

Next step

DA→=−v\overrightarrow{DA}=-\mathbf{v} and AB→=u\overrightarrow{AB}=\mathbf{u}.

Full working

DB→=−v+u=u−v\overrightarrow{DB}=-\mathbf{v}+\mathbf{u}=\mathbf{u}-\mathbf{v}.

4. A point MM is the midpoint of a segment with endpoint position vectors p\mathbf{p} and q\mathbf{q}. Write the position vector of MM.

Hint

A midpoint is halfway between the two endpoints.

Next step

Add the endpoint vectors, then multiply by 12\frac12.

Full working

OM→=12(p+q)\overrightarrow{OM}=\frac12(\mathbf{p}+\mathbf{q}).

5. Use position vectors to show that the diagonals of a parallelogram bisect each other.

Hint

Set one vertex at the origin and label the two side vectors u\mathbf{u} and v\mathbf{v}.

Next step

The other vertices have position vectors u\mathbf{u}, v\mathbf{v} and u+v\mathbf{u}+\mathbf{v}.

Full working

Both diagonal midpoints have position vector 12(u+v)\frac12(\mathbf{u}+\mathbf{v}). Therefore they are the same point and the diagonals bisect each other.

6. Explain why a vector proof can use any chosen origin.

Hint

Think about whether the final equality depends on the labels or on the point locations.

Next step

A different origin changes all position vectors by the same displacement.

Full working

The proof compares positions using consistent vectors. Choosing a different origin shifts each position vector equally, so the geometric equality remains true.

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