GCSE Mathematics (9-1)

19.4 Surface area and volume of prisms and cylinders — Learn

Prerequisites: calculate areas of 2D shapes and multiply lengths; use circle formulae.

Objectives: calculate volumes and surface areas of prisms and cylinders.

Prisms and cylinders

A prism has a repeated end shape, called its cross-section, along its length. Its volume is AhAh, where AA is cross-section area and hh is prism length. For a right prism, surface area is 2A+Ph2A+Ph, where PP is cross-section perimeter. A cylinder is a right prism with circular ends. Its volume is πr2h\pi r^2h. The curved surface unwraps to a rectangle with sides 2πr2\pi r and hh, so its curved area is 2πrh2\pi rh. Add two circular ends for total surface area.

Example 1. A triangular prism has cross-section area 15 cm215\text{ cm}^2 and length 8 cm.

Multiply the cross-section area by the length: 15×8=12015\times8=120.

Its volume is 120 cm3120\text{ cm}^3.

Example 2. A cuboid is 5 cm long, 4 cm wide and 3 cm high. Work out its volume.

Multiply the base area by the height: 5×4×3=605\times4\times3=60.

So its volume is 60 cm360\text{ cm}^3.

Example 3. A triangular prism has cross-section area 6 cm26\text{ cm}^2, cross-section perimeter 12 cm and length 5 cm. Work out its surface area.

Add the two triangular ends and three rectangular faces: 2×6+12×5=722\times6+12\times5=72.

So its surface area is 72 cm272\text{ cm}^2.

Example 4. A cylinder has radius 3 cm and height 7 cm. Find its volume and total surface area.

Use V=πr2hV=\pi r^2h: V=π×32×7=63πV=\pi\times3^2\times7=63\pi.

Add the curved area and two ends: 2π×3×7+2π×32=60π2\pi\times3\times7+2\pi\times3^2=60\pi.

So volume is 63π cm363\pi\text{ cm}^3 and surface area is 60π cm260\pi\text{ cm}^2.

Watch out. Surface area uses square units and volume uses cubic units. A missing face often means you counted an internal join.

Progress check

A cylindrical kerb around the pond has radius 0.50.5 m and length 66 m. Work out its volume in terms of π\pi. Then name its cross-section and the dimensions of its curved surface.

You should now be able to

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