GCSE Mathematics (9-1)

3.3 Laws of indices — Learn

Prerequisites: powers as repeated multiplication; multiplication and division of algebraic terms.

Objectives: simplify products and quotients of powers; simplify a power raised to a power; use zero and negative integer indices.

By the end of this section, you can use index laws to simplify products, quotients and powers, including zero and negative integer indices.

This section covers A4 and N7. An index is the small number that tells how many equal factors a power contains.

Multiply and divide powers

When the base stays the same, multiplying powers joins their factors. Dividing powers removes matching factors.

x3x2=(xxx)(xx)=x5x^3x^2=(xxx)(xx)=x^5 x5x2=xxxxxxx=x3(x≠0)\frac{x^5}{x^2}=\frac{xxxxx}{xx}=x^3 \quad (x\ne0)

For non-zero xx, xaxb=xa+bx^a x^b=x^{a+b} for non-negative integer indices. Also, xa÷xb=xa−bx^a\div x^b=x^{a-b} when b>0b>0, with a non-zero divisor.

Example 1. Simplify a4a3a^4a^3.

a4a3=a4+3a^4a^3=a^{4+3} a4a3=a7a^4a^3=a^7

A power raised to a power

(xa)b(x^a)^b means repeat the whole group xax^a a total of bb times. Therefore the indices multiply.

(x2)3=(x2)(x2)(x2)=x6(x^2)^3=(x^2)(x^2)(x^2)=x^6

Example 2. Simplify (y3)4(y^3)^4.

(y3)4=y3×4(y^3)^4=y^{3\times4} (y3)4=y12(y^3)^4=y^{12}

Zero and negative indices

For non-zero xx, x0=1x^0=1. The quotient law explains this: x3÷x3x^3\div x^3 equals both 1 and x3−3=x0x^{3-3}=x^0.

x0=1(x≠0)x^0=1 \quad (x\ne0)

The same law gives x−2=1/x2x^{-2}=1/x^2, because x3÷x5=x−2x^3\div x^5=x^{-2} and x3/x5=1/x2x^3/x^5=1/x^2.

Watch out. In x3x4x^3x^4, add the indices to get x7x^7. In (x3)4(x^3)^4, multiply them to get x12x^{12}. The brackets show that the whole power repeats. Check by writing out the factors.

Progress check

Rewrite 2202^{20} as (210)2(2^{10})^2. Use 210=10242^{10}=1024 to find the exact size after 20 doublings. Compare the result with your estimate from 3.2.

Try it: the laws of indices

Predict first. Without multiplying, predict 23×222^3\times2^2 and 23+22^{3+2}. Then calculate each expression to test your prediction.

Explain: why is am×an=am+na^m\times a^n=a^{m+n}? Describe how many factors of aa the product contains.

You should now be able to

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