GCSE Mathematics (9-1)

10.4 The nth term of a quadratic sequence — Learn

Prerequisites: square numbers, linear sequences, and collecting like terms.

Objectives: use constant second differences to find a quadratic nth term. This section develops the Higher content in A25.

First and second differences

The first differences are the changes between consecutive terms. The second differences are the changes between consecutive first differences.

For a quadratic sequence, the second differences are constant. That constant is twice the coefficient of n2n^2.

Example 1. Find the nth term of 2,7,16,29,…2,7,16,29,\ldots.

First differences are 5,9,135,9,13. Second differences are 4,44,4. So start with 2n22n^2.

2n2:2,8,18,32,…2n^2: 2,8,18,32,\ldots

Subtract these terms from the given terms:

2−2=0,7−8=−1,16−18=−2,29−32=−32-2=0,\quad 7-8=-1,\quad 16-18=-2,\quad 29-32=-3

The differences follow 1−n1-n, so the rule is 2n2−n+12n^2-n+1.

Check at position 44:

2(4)2−4+1=32−4+1=292(4)^2-4+1=32-4+1=29

Progress check. Pattern A has constant first differences, so it is linear. Pattern B doubles, so its terms do not have constant second differences.

Watch out. The constant second difference is not the coefficient of n2n^2. Divide it by 22, then check your rule against the original terms.

You should now be able to

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