A-level Mathematics

Chapter 9: Numerical methods

The chapter problem: the landing drone and the river survey

A delivery drone starts its descent 4040 metres above a landing pad. Its height hh metres, tt seconds after the descent begins, is modelled by

h(t)=40e−t/4−2t.h(t) = 40e^{-t/4} - 2t.

The drone lands when h=0h = 0. No rearrangement or standard function solves 40e−t/4−2t=040e^{-t/4} - 2t = 0 exactly, so the landing time has to be found by a numerical method. The model is not perfect, but it answers the question the operator needs: how long until the rotors stop?

The second question comes from a river survey. An engineer measures the water depth every 22 metres across a 1212 metre channel:

Distance across (m) 00 22 44 66 88 1010 1212
Depth (m) 00 1.21.2 2.52.5 3.13.1 2.42.4 0.90.9 00

The cross-sectional area of the water is needed to find the flow rate. The survey gives a table of heights, not a formula, so the area is estimated from the readings rather than integrated exactly.

By the end of the chapter you will answer both parts. You will show that the landing time lies between two whole seconds, then narrow the interval and use a recurrence relation to reach an answer correct to three decimal places. You will also estimate the channel's cross-sectional area from the table, and explain why the answer is an estimate rather than an exact value.

First contact — no working needed yet. Look at the height model. At t=0t = 0 the drone is 4040 m up. Predict whether the drone lands before or after 66 seconds, and write down one reason for your prediction.

Then look at the depth table. The depths do not follow a straight line. Predict whether the cross-sectional area is larger or smaller than the rectangle 12×2=2412 \times 2 = 24 square metres. Write your prediction down before you read on.

If you are not sure where to start

For the drone, work out the height at 55 seconds and at 66 seconds by substituting into the model. If the height changes sign between the two times, the drone lands somewhere in between.

For the channel, add up the six depths and divide by 66 to estimate the mean depth. Multiply the mean depth by the width of the channel.

By the end of this chapter you will be able to

Where it is used

Most equations that describe the real world have no exact solution. An engineer sizing a beam, a pharmacist computing a dose or a pilot finding a flight path meets equations such as x+ln⁡x=3x + \ln x = 3 or ex=3xe^x = 3x, and there is no formula for the answer. Numerical methods turn those equations into arithmetic a computer can repeat until the answer is close enough.

The same idea runs the other way. When a quantity is measured rather than described by a formula, the readings come as a table, and the area or volume between them is estimated from the points that were recorded. Weather data, vehicle speed traces and medical scans are all handled this way.

Numerical methods also connect to calculus. Chapter 7 measured a gradient from a shrinking chord, and Chapter 8 measured an area from thin strips. Both are numerical ideas at heart, and the trapezium rule is the next step on from the strip sums of Section 8.4.

Your turn to connect it

Think of a time you had to measure or work out something that had no simple formula. It could be the amount of paint for a curved wall, the time a journey will take, or the number of people at a festival. Write down the quantity, why an exact method is hard, and whether you would need a very close answer or a rough one. Keep your answer for the Review.

Roadmap

  1. 9.1 Locating roots by change of sign
  2. 9.2 Simple iterative methods, cobweb and staircase diagrams
  3. 9.3 Newton–Raphson and other recurrence relations
  4. 9.4 The trapezium rule and limits on the estimate
  5. 9.5 Numerical methods in context
  6. Review

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