A-level Mathematics

1.1 Statements, assumptions and the structure of a proof — Practise with help

Work each one first, closed book. Reveal a hint only if you are stuck, the next step to see the first move, and the full working only to check.

Warm-up: remember

  1. Write down the first five prime numbers.
  2. Work out the value of n2+1n^2 + 1 when n=5n = 5.
  3. Is 22 an even number? Is 22 a prime number?
Answers
  1. 22, 33, 55, 77, 1111.
  2. 52+1=265^2 + 1 = 26.
  3. Yes, and yes. It is the only even prime.

Practise with help

1. Which of these are statements? For each statement, say whether it is true or false. (a) 99 is prime (b) Solve x+1=2x + 1 = 2 (c) 4+5=94 + 5 = 9.

Hint

A statement is a sentence that is either true or false. Check each sentence for a question mark, an instruction, or a letter whose value is not fixed.

Next step

Take the first sentence on its own. "9 is prime" claims something specific, so test it by looking for a factor of 99.

Full working

(a) A statement, and false: 9=3×39 = 3 \times 3, so 99 has a factor other than 11 and itself.

(b) Not a statement: "Solve" is an instruction, not a claim.

(c) A statement, and true: 4+5=94 + 5 = 9.

2. Write the assumption and the conclusion of: "If a shape is a square, then it has four sides."

Hint

The assumption is the part after "if". The conclusion is the part after "then".

Next step

Write the sentence underneath in the form "if AA then BB", then copy AA and BB into two separate lines.

Full working

Assumption: the shape is a square.

Conclusion: the shape has four sides.

3. Write the converse of the statement in question 2, and give a shape that shows the converse is false.

Hint

Swap the assumption and the conclusion. The converse starts with "If it has four sides".

Next step

Write the converse in full, then look for a four-sided shape that is not a square.

Full working

Converse: "If a shape has four sides, then it is a square."

The converse is false. A rectangle that is 33 cm by 44 cm has four sides, but it is not a square. The original statement is true and its converse is false, so the two directions are independent.

4. The statement is: "If nn is a multiple of 33, then nn is a multiple of 99." Test it with n=3n = 3 and n=9n = 9.

Hint

The assumption is "a multiple of 33", so both values satisfy the assumption. Now check the conclusion for each value.

Next step

Work out 3÷93 \div 9 and 9÷99 \div 9 as whole-number divisions with remainders.

Full working

For n=3n = 3: the assumption holds, since 3=3×13 = 3 \times 1. The conclusion fails, since 33 is not a multiple of 99.

For n=9n = 9: the assumption holds, and the conclusion holds, since 9=9×19 = 9 \times 1.

The value n=3n = 3 shows the statement is false. One counter example is enough.

5. Disprove the statement "For every real number xx, x2>xx^2 > x" by finding one value of xx.

Hint

Look for a value between 00 and 11. Squaring a number in that range makes it smaller, not larger.

Next step

Try x=12x = \frac{1}{2} and work out x2x^2.

Full working

Take x=12x = \frac{1}{2}. Then

x2=14.x^2 = \frac{1}{4}.

Now

14<12,\frac{1}{4} < \frac{1}{2},

so x2>xx^2 > x is false for this value. The statement says "for every real number", so one counter example disproves it.

6. Return to the chapter problem. For Claim B, work out the value of n2+n+41n^2 + n + 41 when n=40n = 40, and show that the value is not prime.

Hint

Substitute 4040 for nn and work out the three terms separately before adding them.

Next step

Work out 40240^2, then add 4040, then add 4141, and look at the total.

Full working

For n=40n = 40,

n2+n+41=1600+40+41=1681.n^2 + n + 41 = 1600 + 40 + 41 = 1681.

But

1681=41×41,1681 = 41 \times 41,

so the value has a factor other than 11 and itself. It is not prime, and Claim B is false.

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