A-level Mathematics

Chapter 7: Differentiation

The chapter problem: the open box and the rising balloon

A sheet of card measures 1616 cm by 1010 cm. Four equal squares of side xx cm are cut from the corners, and the sides are folded up to make an open box.

The volume of the box is

V=x(16−2x)(10−2x).V = x(16 - 2x)(10 - 2x).

The largest volume is not at the largest square, and it is not at the smallest. Calculus finds the exact value of xx that gives the greatest volume.

A spherical balloon is inflated for a display. Its volume increases at a steady rate of 100100 cm3^3 per second, so

dVdt=100.\frac{dV}{dt} = 100.

The radius rr grows too. Its rate of growth is linked to the rate at which the volume grows. Calculus finds drdt\dfrac{dr}{dt} at any radius, and shows how the rate changes as the balloon swells.

By the end of the chapter you will answer both parts exactly. You will write the volume of the box as a function of xx, find where its gradient is zero, and prove that the point gives a maximum. You will also connect the two rates and find the speed at which the radius grows when r=5r = 5 cm.

First contact — no working needed yet. Look at the box. If x=0x = 0 the box is flat, and if x=5x = 5 the card is cut in two and there is no box. Predict the value of xx between 00 and 55 that gives the greatest volume. Write your prediction down before you read on.

Then look at the balloon. It starts small and swells. Predict whether the radius grows faster at the start, or later when the balloon is large. Write one sentence to explain your prediction.

If you are not sure where to start

For the box, work out the volume for a few values of xx. Try x=1x = 1, x=2x = 2 and x=3x = 3. The largest of the three is closer to the greatest volume, but the exact value needs calculus.

For the balloon, the volume grows at a steady 100100 cm3^3 each second. A balloon of radius 55 cm holds much more air than one of radius 11 cm. Adding the same volume to a large balloon spreads over a bigger surface, so the radius grows more slowly as the balloon swells.

By the end of this chapter you will be able to

Where it is used

Differentiation is the mathematics of change. Engineers use it to design a container that uses the least material, economists use it to find the price that gives the greatest profit, and physicists use it for speed and acceleration. Every rate in a science is a derivative. The rules in this chapter turn a description of how a quantity changes into an equation, and that equation is where the next chapter, on integration, begins.

Your turn to connect it

Think of a quantity that grows or shrinks. It could be the water in a tank, the charge left in a battery, a savings balance, the height of a plant, or the temperature of a drink. Write down what you would measure, how fast it changes, and whether the rate itself changes as the quantity grows.

Roadmap

  1. 7.1 The derivative as a gradient and a rate of change
  2. 7.2 Differentiation from first principles
  3. 7.3 Differentiating powers, exponentials, trigonometric functions and logarithms
  4. 7.4 The second derivative, convexity and points of inflection
  5. 7.5 Tangents, normals, maxima, minima and stationary points
  6. 7.6 Increasing and decreasing functions
  7. 7.7 The product, quotient and chain rules
  8. 7.8 Connected rates of change and inverse functions
  9. 7.9 Implicit and parametric differentiation
  10. 7.10 Constructing differential equations
  11. Review

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