A-level Mathematics

1.1 Statements, assumptions and the structure of a proof — Practise

Work through these on your own. For each item, write down whether you are proving a "for all" statement, disproving it, or showing "there is". The method matters as much as the answer.

Both the questions and the answers below come from a set that is checked by computer every time the book is built.

  1. Decide whether each statement is true or false. (a) 2+3=62 + 3 = 6 (b) 1212 is a multiple of 44 (c) 7<37 < 3.
  2. A statement says: "If a whole number is a multiple of 66, then it is a multiple of 33." (a) Write the assumption. (b) Write the conclusion. (c) Test the statement with the number 4242.
  3. A statement says: "If nn is a multiple of 44, then nn is even." (a) Write the converse. (b) Give a value of nn that shows the converse is false.
  4. The statement "For every real number xx, x2≥xx^2 \geq x" is false. Find a value of xx that shows this.
  5. Show that there is a whole number nn for which n2+n+1n^2 + n + 1 is a multiple of 33.
  6. Work out the value of n2+n+41n^2 + n + 41 for n=1n = 1, n=2n = 2 and n=3n = 3.
  7. Decide whether each number is prime: (a) 99 (b) 1111.
  8. A student checks n=1,2,3,4,5n = 1, 2, 3, 4, 5 and finds that n2+n+41n^2 + n + 41 is prime each time. The student says: "This proves the claim for every whole number nn." Explain what is wrong with the reasoning.
  9. A whole number nn is a multiple of 66. Show that nn is also a multiple of 33.
  10. The statement "If nn is a multiple of 33, then nn is a multiple of 99" is false. Give a value of nn that shows this.
Answers and concise solutions

1. True or false

Answer: (a) false, because 2+3=52 + 3 = 5 (b) true, because 12=3×412 = 3 \times 4 (c) false, because 7>37 > 3.

2. Assumption, conclusion and a test

Answer: Assumption: the number is a multiple of 66. Conclusion: the number is a multiple of 33. For 4242: 42=6×742 = 6 \times 7, so the assumption holds, and 42=3×1442 = 3 \times 14, so the conclusion holds too.

3. The converse and a counter example

Answer: (a) Converse: "If nn is even, then nn is a multiple of 44." (b) Take n=2n = 2. The number 22 is even, but 22 leaves remainder 22 on division by 44, so it is not a multiple of 44.

4. A value of xx

Answer: Take x=12x = \frac{1}{2}. Then x2=14x^2 = \frac{1}{4}, and 14<12\frac{1}{4} < \frac{1}{2}, so x2≥xx^2 \geq x fails.

5. A value of nn

Answer: For n=1n = 1, n2+n+1=3n^2 + n + 1 = 3, which is a multiple of 33. One example is enough, because the statement says "there is".

6. The three values

Answer: (a) 4343 (b) 4747 (c) 5353.

7. Prime or composite

Answer: (a) 9=3×39 = 3 \times 3, so 99 is not prime. (b) 11\sqrt{11} lies between 33 and 55, so the only primes to test are 22 and 33. Neither divides 1111, so 1111 is prime.

8. The flaw in the reasoning

Answer: The five values are prime, so the checking is correct. But the claim is about every whole number, and there are infinitely many. A finite check is evidence, not proof: an untested value might still fail, and one later does. A proof needs a general argument that covers every value at once.

9. Show the conclusion

Answer: Write n=6kn = 6k, because nn is a multiple of 66. Then n=3×(2k)n = 3 \times (2k). The factor 2k2k is a whole number, so nn is a multiple of 33.

10. A value of nn

Answer: Take n=3n = 3. The number 33 is a multiple of 33, but it is not a multiple of 99. One such value is enough to show the statement is false.

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