A-level Mathematics

Chapter 6: Exponentials and logarithms

The chapter problem: the cooling coffee and the growing culture

A cup of coffee is poured at 80∘80^\circC in a room kept at 20∘20^\circC. The temperature above room temperature, E=T−20E = T - 20, falls as the coffee cools:

E=60e−kt,E = 60e^{-kt},

where EE is in degrees Celsius and tt is in minutes. After 1010 minutes the coffee is at 65∘65^\circC, so the excess temperature is 45∘45^\circC. The coffee is ready to drink when its excess temperature is 15∘15^\circC, that is, when the coffee reaches 35∘35^\circC. The cooling constant kk is not given, and it has to be found from the one measurement.

A laboratory also grows a mould culture. The number of cells NN is measured each hour:

Time tt (hours) 00 11 22 33
Number NN 200200 300300 450450 675675

The team believes the growth follows N=kbtN = kb^t, where bb is the factor by which the number multiplies each hour. They want to estimate bb from the data, and then predict when the number will reach 20002000.

By the end of the chapter you will answer both parts. You will find the cooling constant from the measurement, read the growth factor from the table, find the time to cool and the time to double, and connect each model to its rate of change.

First contact — no working needed yet. Look at the coffee. It cools quickly while it is hot, then more slowly as it approaches room temperature. Predict how long the coffee takes to fall from 80∘80^\circC to 65∘65^\circC, compared with the time to fall from 65∘65^\circC to 35∘35^\circC. Write both guesses down.

Then look at the table. Each number is bigger than the one before it. Work out the ratio between one count and the next, and use it to predict the count at t=4t = 4 hours.

If you are not sure where to start

For the coffee, the first 1515 degrees are lost while the coffee is hot, so they are lost quickly. The next 3030 degrees are lost while the coffee is cooler, so they take longer. The first stage is faster, but the second stage covers twice as many degrees.

For the culture, divide each count by the one before it: 300÷200=1.5300 \div 200 = 1.5, and 450÷300=1.5450 \div 300 = 1.5. The pattern is to multiply by 1.51.5 each hour, so the count at t=4t = 4 is about 675×1.5=1012.5675 \times 1.5 = 1012.5. Section 6.5 turns this pattern into a straight-line estimate.

By the end of this chapter you will be able to

Where it is used

Exponentials describe anything that grows or shrinks by a fixed factor in equal steps of time. Money in a savings account, a population of bacteria, a dose of medicine, a radioactive sample and the charge in a capacitor all follow the same curve. Logarithmic scales turn that curve into a straight line, which is how scientists read a growth constant from a graph. The exponential function is also the one function whose slope equals its value, so it sits at the heart of calculus. The next chapter differentiates ekxe^{kx} and ln⁡x\ln x, and the chapter after integrates them.

Your turn to connect it

Think of something in your own life that grows or shrinks by a fixed factor. It could be a savings balance, a rumour spreading, a phone battery draining, or a cooling drink. Write down the quantity, the factor for each time step, and one question about it that a graph could answer.

Roadmap

  1. 6.1 The functions a^x and e^x
  2. 6.2 The gradient of e^kx and the exponential model
  3. 6.3 Logarithms and the laws of logarithms
  4. 6.4 Solving equations of the form a^x = b
  5. 6.5 Logarithmic graphs and estimating parameters
  6. 6.6 Exponential growth and decay in modelling
  7. Review

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