A-level Mathematics

13.5 Selecting an appropriate distribution — Learn

Prerequisites: the binomial model from Sections 13.1 and 13.2; the Normal model from Section 13.3; the Normal approximation from Section 13.4; the modelling ideas from Sections 2.12 and 6.6.

By the end of this section you can: decide whether a binomial or a Normal model fits a context; give a reason for the choice; and recognise when neither model is appropriate.

1. Two models, two kinds of quantity

The chapter has built two models. They answer different kinds of question.

Binomial B(n,p)B(n, p) Normal N(μ,σ2)N(\mu, \sigma^2)
Quantity A count of successes A measurement
Values Whole numbers from 0 to nn Any value in a range
Shape Bars, possibly skewed A symmetric bell curve
Parameters Number of trials nn, success probability pp Mean μ\mu, standard deviation σ\sigma
Typical use How many pass, fail or recover How long, how heavy, how far

The first move in a modelling question is to decide whether the quantity is a count or a measurement.

2. Choosing the binomial

Check the four conditions from Section 13.1.

  1. A fixed number nn of trials.
  2. Two outcomes on each trial.
  3. A constant probability pp of success.
  4. Independent trials.

If all four hold, the binomial model fits. Common examples are the number of defective items in a fixed sample, the number of people in a fixed group who respond, and the number of correct guesses on a fixed test.

3. Choosing the Normal

The Normal model fits a measurement that varies about a mean in a symmetric, bell-shaped way. Common examples are heights, masses, times and errors.

The Normal model is also used as an approximation to a binomial count when nn is large and pp is not close to 0 or 1, as you saw in Section 13.4. In that case the count is still a count, and the Normal curve only stands in for the bars.

4. When the models do not fit

A model is a simplifying assumption, and some contexts break it.

When the binomial model may not be appropriate:

When the Normal model may not be appropriate:

Example 1. A factory makes 4 000 parts a day. A quality inspector checks 50 parts and counts the number that are faulty. Which model fits the count?

The number of trials is fixed at 50. Each part is either faulty or not, so there are two outcomes. If the parts are checked in a random order, the trials are independent. Then a binomial model fits, with n=50n = 50 and pp the proportion faulty.

Example 2. A machine fills bags of rice. The mass of a bag varies. Which model fits the mass?

The mass is a measurement, not a count. Filling errors tend to be symmetric about the target mass, with small errors more common than large ones. A Normal model fits the mass.

Example 3. A bag holds 6 red and 4 blue counters. Three counters are taken without replacement. Let XX be the number of red counters. Which model fits?

The probability of a red counter changes after each draw, so pp is not constant. The binomial model does not fit. XX is a whole number from 0 to 3, so a Normal model does not fit either. Neither model is appropriate. The exact probabilities can be found by counting equally likely selections.

Example 4. The number of goals scored in a football match. Which model fits?

The number of goals is a count from 0 upwards. There is no fixed number of trials, so the binomial model does not fit. The distribution is not symmetric, so a Normal model does not fit either. A different model is needed, and it is outside this chapter.

5. The modelling cycle

Choosing a model is a cycle, not a single decision.

  1. Choose a model from the context.
  2. Calculate the probability or the estimate.
  3. Check the model against the data. Do the values look symmetric? Are the parameters plausible?
  4. Refine the model if the check fails, and repeat.

Write down the assumptions you made. A conclusion is only as strong as its assumptions, and stating them shows the reader what the answer depends on.

6. Progress check

Return to the chapter problem. The supplier claims that each of 20 seeds germinates with probability 0.8, independently, and that the height of a mature plant is normally distributed with mean 45 cm and standard deviation 6 cm.

Decide which model fits each quantity, and give a reason.

Answer

The number of seeds that germinate is a count. There are 20 independent trials, each seed either germinates or does not, and the probability 0.8 is the same for every seed. So the number that germinate fits the binomial model, X∼B(20,0.8)X \sim B(20, 0.8).

The height of a plant is a measurement. Heights vary about a mean in a roughly symmetric way. A standard deviation of 6 cm about a mean of 45 cm is consistent with the model, because 45 cm is several standard deviations above 0. So the height fits the Normal model, X∼N(45,62)X \sim N(45, 6^2).

Watch out. Three mistakes are common.

Choosing a model from the average alone. A question that mentions an average is not automatically Normal. Ask first whether the quantity is a count or a measurement.

Using the Normal model for a count. A count takes whole-number values from 0 upwards. A Normal curve would give a positive probability to values between whole numbers and to negative values. Use the Normal curve only as an approximation, and only when np>5np > 5 and n(1−p)>5n(1-p) > 5.

Ignoring dependence. Taking items without replacement from a small group makes the trials dependent. The binomial model needs independence.

Re-check: name the quantity, decide count or measurement, then test the model against its conditions.

You should now be able to

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