A-level Mathematics

2.1 Laws of indices for rational exponents — Learn

Prerequisites: integer powers; square roots and cube roots; multiplying and dividing fractions; the index laws for whole-number exponents.

By the end of this section you can: write a root as a power; evaluate an expression such as 163416^{\frac{3}{4}}; apply the index laws with fractional and negative exponents; and solve an equation in which the unknown is a base with a rational exponent.

1. The index laws you already know

An index (or power) counts repeated multiplication. For a base aa and whole numbers mm and nn:

am×an=am+n,aman=am−n,(am)n=amn.a^m \times a^n = a^{m+n}, \qquad \frac{a^m}{a^n} = a^{m-n}, \qquad \left(a^m\right)^n = a^{mn}.

These laws work for every exponent, not only whole numbers. Two more follow from them.

a0=1anda−n=1an.a^0 = 1 \qquad \text{and} \qquad a^{-n} = \frac{1}{a^n}.

The second law turns a negative index into a reciprocal. For example, 5−2=1255^{-2} = \frac{1}{25} and (23)−1=32\left(\frac{2}{3}\right)^{-1} = \frac{3}{2}.

2. A root is a fractional power

The square root of aa is the number whose square is aa. We write a=a12\sqrt{a} = a^{\frac{1}{2}}, because

a12×a12=a12+12=a1=a.a^{\frac{1}{2}} \times a^{\frac{1}{2}} = a^{\frac{1}{2} + \frac{1}{2}} = a^{1} = a.

In the same way, the nnth root is the power 1n\frac{1}{n}:

a1n=an.a^{\frac{1}{n}} = \sqrt[n]{a}.

A power with a numerator builds on this. The numerator counts how many times the root is repeated, and the denominator names the root:

amn=(an)m=amn.a^{\frac{m}{n}} = \left(\sqrt[n]{a}\right)^m = \sqrt[n]{a^m}.

For example, 823=(83)2=22=48^{\frac{2}{3}} = \left(\sqrt[3]{8}\right)^2 = 2^2 = 4. When you evaluate by hand, take the root first and raise the result to the power. The numbers stay small that way.

Example 1. Work out 163416^{\frac{3}{4}}.

Take the fourth root first:

1634=(164)3.16^{\frac{3}{4}} = \left(\sqrt[4]{16}\right)^3.

The fourth root of 1616 is 22, because 24=162^4 = 16. Raise 22 to the power 33:

(164)3=23=8.\left(\sqrt[4]{16}\right)^3 = 2^3 = 8.

Example 2. Work out 125−13125^{-\frac{1}{3}}.

The negative sign gives a reciprocal:

125−13=112513.125^{-\frac{1}{3}} = \frac{1}{125^{\frac{1}{3}}}.

The cube root of 125125 is 55:

112513=15.\frac{1}{125^{\frac{1}{3}}} = \frac{1}{5}.

3. The laws in algebra

The same laws simplify expressions with a letter base. Add the exponents when you multiply, subtract when you divide, and multiply when a power is raised to a power.

Example 3. Simplify x12×x32x^{\frac{1}{2}} \times x^{\frac{3}{2}}, where x>0x > 0.

Add the exponents:

x12×x32=x12+32=x2.x^{\frac{1}{2}} \times x^{\frac{3}{2}} = x^{\frac{1}{2} + \frac{3}{2}} = x^{2}.

Example 4. Simplify (8x6)23\left(8x^6\right)^{\frac{2}{3}}, where x>0x > 0.

The power applies to each factor inside the bracket:

(8x6)23=823×(x6)23.\left(8x^6\right)^{\frac{2}{3}} = 8^{\frac{2}{3}} \times \left(x^6\right)^{\frac{2}{3}}.

Now 823=48^{\frac{2}{3}} = 4, and the power of a power multiplies the exponents:

4×x6×23=4x4.4 \times x^{6 \times \frac{2}{3}} = 4x^{4}.

4. Solving an equation with a rational exponent

To free an unknown from an exponent, raise both sides to the reciprocal power.

Example 5. Solve x23=9x^{\frac{2}{3}} = 9.

The reciprocal of 23\frac{2}{3} is 32\frac{3}{2}. Raise both sides to that power:

(x23)32=932.\left(x^{\frac{2}{3}}\right)^{\frac{3}{2}} = 9^{\frac{3}{2}}.

The left side becomes x1=xx^1 = x, and the right side becomes 2727:

x=27.x = 27.

There is a second solution. The exponent 23\frac{2}{3} has an even numerator, so a negative base gives the same value:

(−27)23=(−273)2=(−3)2=9.(-27)^{\frac{2}{3}} = \left(\sqrt[3]{-27}\right)^2 = (-3)^2 = 9.

So x=27x = 27 or x=−27x = -27. Check both values in the original equation before you finish.

Watch out. Three traps appear with rational exponents.

Splitting a root over a sum. The law a1nb1n=(ab)1na^{\frac{1}{n}} b^{\frac{1}{n}} = (ab)^{\frac{1}{n}} joins a product, not a sum. 9+16=5\sqrt{9 + 16} = 5, but 9+16=7\sqrt{9} + \sqrt{16} = 7, so a+b\sqrt{a + b} is not a+b\sqrt{a} + \sqrt{b}.

A negative index and a negative number. 2−32^{-3} means 123=18\frac{1}{2^3} = \frac{1}{8}; it does not mean −8-8. The minus sign in the exponent moves the base to the other part of a fraction.

A lost root. Raising both sides to an even power can hide a second solution, and raising to the power 32\frac{3}{2} needs a non-negative base. Re-check: after solving, substitute each value back, and ask whether the base is allowed to be negative.

Progress check

  1. Write x3\sqrt[3]{x} as a power of xx.
  2. Work out 813481^{\frac{3}{4}} by taking the root first.
  3. Solve x32=8x^{\frac{3}{2}} = 8.
  4. Explain why x12x^{\frac{1}{2}} has no real value when x=−4x = -4.

You should now be able to

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