GCSE Mathematics (9-1)

10.3 The nth term of a linear sequence — Learn

Prerequisites: times tables, substitution, and position-to-term rules.

Objectives: find an expression for the nth term of a linear sequence and use it to find a specified term. This section covers A25.

The common difference

A linear sequence has the same difference between consecutive terms. This difference is called the common difference.

For 7,11,15,19,…7,11,15,19,\ldots, the common difference is 44. The coefficient of nn in its rule is 44, so start with 4n4n.

Example 1. Find the nth term of 7,11,15,19,…7,11,15,19,\ldots.

The 4n4n sequence is 4,8,12,16,…4,8,12,16,\ldots. Each given term is 33 more.

4n+34n+3

Check position 11: 4(1)+3=74(1)+3=7. Check position 22: 4(2)+3=114(2)+3=11.

A decreasing sequence

The common difference can be negative.

Example 2. Find the nth term of 12,9,6,3,…12,9,6,3,\ldots.

The common difference is −3-3, so start with −3n-3n.

At position 11, −3(1)=−3-3(1)=-3. Add 1515 to reach the first term, 1212.

−3n+15-3n+15

Check position 22: −3(2)+15=9-3(2)+15=9.

Progress check. Pattern A has 5,8,11,14,…5,8,11,14,\ldots. Its nth term is 3n+23n+2, so design 5 contains 3(5)+2=173(5)+2=17 tiles.

Watch out. Using the first term as the constant often gives the wrong rule. First match the common difference, then adjust the constant and check positions 11 and 22.

You should now be able to

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