GCSE Physics (9-1)

7.2 Magnetic effects of currents and the motor effect — Practise with help

Work each problem first. Open a hint only if you are stuck, and the full working only to check.

Warm-up: remember

Answer these from memory. They use ideas from Sections 7.1 and 6.1.

  1. A steel paper clip is placed in the field of a magnet and then taken away. Does it stay magnetic? Explain.
  2. What is the unit of electric current, and what letter is used for current in an equation?
Answers
  1. It loses most or all of its magnetism. It became an induced magnet only while it was in the field.
  2. The unit is the ampere, and the symbol is II.

If question 1 went wrong, look again at induced magnets in Section 7.1. If question 2 went wrong, look at current in Section 6.1.

Practise with help

1. Describe how to show that a current in a wire creates a magnetic field.

Hint

Use a compass, because a compass needle turns when it sits in a magnetic field.

Next step

Place the compass near a straight wire. Note where it points with the current off, then switch the current on.

Full working

Place a long straight wire on a piece of card and put a compass near it. With the current off, the compass points north. Switch the current on. The needle turns away from north, so the current has made a magnetic field. Reverse the current, and the needle turns the other way. This is a model answer for you to compare with your own wording.

2. Describe the magnetic field around a long straight wire, and explain how it changes as you move away from the wire.

Hint

Picture looking along the wire. The field lines form closed loops.

Next step

Say that the field lines are circles around the wire, then say what happens to the field strength as the distance grows.

Full working

The field lines are circles around the wire. The field is strongest close to the wire. As you move further away, the field gets weaker. A larger current makes the field stronger at every distance.

3. Explain how shaping a wire into a solenoid increases the magnetic effect of the current.

Hint

Think about what happens to the field of each turn of the coil.

Next step

Say that the field of each turn adds to the field of the other turns, then describe the field inside the coil.

Full working

A solenoid is a coil of many turns. The magnetic field of each turn adds to the field of the other turns, so the fields combine. Inside the solenoid the field is strong and uniform, and outside it the field has the shape of the field of a bar magnet. The magnetic effect is much larger than for one straight wire.

4. Explain why an iron core is added to a solenoid to make an electromagnet, and how the magnet can be switched off.

Hint

Iron is a magnetic material. Think about what the field of the coil does to the iron.

Next step

Say that the iron becomes magnetised by the coil's field and adds to it. Then say what happens to the field when the current stops.

Full working

The field of the coil magnetises the iron core. The magnetised core adds its own field to the field of the coil, so the total field is much stronger. When the current is switched off, the coil's field goes and the iron loses its magnetism, so the electromagnet can be switched off.

5. Describe the magnetic field inside a solenoid.

Hint

Compare the field inside the coil with the field around a bar magnet.

Next step

Say whether the field inside is strong or weak, and whether it is uniform.

Full working

Inside the solenoid the field is strong and uniform. The field lines are straight and equally spaced, and they point along the axis of the coil. Outside the solenoid the field spreads out and has the same shape as the field of a bar magnet.

6. State Fleming's left-hand rule, and say what each part of the hand represents.

Hint

Hold your left hand with the thumb and the first two fingers at right angles.

Next step

Name the field, the current and the force, and match each one to a finger or the thumb.

Full working

Hold the left hand so that the thumb, the first finger and the second finger are at right angles to each other. The first finger points in the direction of the magnetic field, from north to south. The second finger points in the direction of the current. The thumb points in the direction of the force on the conductor.

7. A wire of length 0.20 m carries a current of 3.0 A. It is at right angles to a magnetic field of flux density 0.40 T. Calculate the force on the wire.

Hint

The three quantities you need are BB, II and ll. Check that each is in its SI unit before you multiply.

Next step

Write F=BIlF = BIl, then put in B=0.40B = 0.40 T, I=3.0I = 3.0 A and l=0.20l = 0.20 m.

Full working F=BIl=0.40×3.0×0.20=0.24 N\begin{aligned} F &= B I l \\ &= 0.40 \times 3.0 \times 0.20 \\ &= 0.24\,\text{N} \end{aligned}

8. The force on a wire is 0.60 N. The wire is 0.50 m long and sits at right angles to a magnetic field of flux density 0.30 T. Calculate the current in the wire.

Hint

You want the current, so rearrange F=BIlF = BIl before you put the numbers in.

Next step

Write I=FBlI = \dfrac{F}{Bl}, then work out 0.600.30×0.50\dfrac{0.60}{0.30 \times 0.50}.

Full working F=BIlI=FBl=0.600.30×0.50=4.0 A\begin{aligned} F &= B I l \\ I &= \frac{F}{B l} \\ &= \frac{0.60}{0.30 \times 0.50} \\ &= 4.0\,\text{A} \end{aligned}

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