GCSE Physics (9-1)

4.1 Waves in air, fluids and solids — Practise

Work through these on your own. Keep your working neat: the method matters as much as the answer.

Both the questions and the answers below come from a set that is checked by computer every time the book is built.

  1. A ripple tank makes water waves with a frequency of 4.0 Hz and a wavelength of 0.15 m. Calculate the wave speed.
  2. A sound wave in air has a frequency of 165 Hz. The speed of sound in air is 330 m/s. Calculate the wavelength.
  3. A wave travels along a rope at 12 m/s. The wavelength is 3.0 m. Calculate the frequency.
  4. A sound wave has a frequency of 50 Hz. Calculate its period.
  5. A wave has a period of 0.40 s. Calculate its frequency.
  6. An ultrasound scanner uses a frequency of 2.5 MHz. Convert this frequency to hertz.
  7. A longitudinal wave in a metal bar has a frequency of 1000 Hz and a wavelength of 5.0 m. Calculate the wave speed.
  8. Ten waves pass a point in 4.0 s. Calculate the frequency and the period of the waves.
  9. Describe the difference between a transverse wave and a longitudinal wave. Give one example of each.
  10. A cork floats on water. A water wave passes the cork and the cork bobs up and down but does not move along with the wave. Explain what this shows about what a wave transfers.
  11. Describe a method to measure the speed of sound in air using an echo from a wall.
  12. A water wave travels 24 m in 8.0 s. Calculate the wave speed.
Answers and concise solutions

1. Wave speed of the ripples

Answer: v=fλ=4.0×0.15=0.60 m/sv = f\lambda = 4.0 \times 0.15 = 0.60\,\text{m/s}.

2. Wavelength of the sound wave

Answer: v=fλv = f\lambda, so λ=vf=330165=2.0 m\lambda = \dfrac{v}{f} = \dfrac{330}{165} = 2.0\,\text{m}.

3. Frequency of the wave on the rope

Answer: v=fλv = f\lambda, so f=vλ=123.0=4.0 Hzf = \dfrac{v}{\lambda} = \dfrac{12}{3.0} = 4.0\,\text{Hz}.

4. Period of the sound wave

Answer: T=1f=150=0.020 sT = \dfrac{1}{f} = \dfrac{1}{50} = 0.020\,\text{s}.

5. Frequency of the wave

Answer: T=1fT = \dfrac{1}{f}, so f=1T=10.40=2.5 Hzf = \dfrac{1}{T} = \dfrac{1}{0.40} = 2.5\,\text{Hz}.

6. Frequency in hertz

Answer: The prefix mega means one million, so 2.5 MHz=2.5×106 Hz=2500000 Hz2.5\,\text{MHz} = 2.5 \times 10^6\,\text{Hz} = 2500000\,\text{Hz}.

7. Wave speed in the metal bar

Answer: v=fλ=1000×5.0=5000 m/s=5.0×103 m/sv = f\lambda = 1000 \times 5.0 = 5000\,\text{m/s} = 5.0 \times 10^3\,\text{m/s}.

8. Frequency and period

Answer: f=104.0=2.5 Hzf = \dfrac{10}{4.0} = 2.5\,\text{Hz}. The period is T=1f=12.5=0.40 sT = \dfrac{1}{f} = \dfrac{1}{2.5} = 0.40\,\text{s}.

9. Transverse and longitudinal waves

  • In a transverse wave the vibration is at right angles to the direction in which the wave travels.
  • In a longitudinal wave the vibration is along the same line as the direction in which the wave travels, so the wave has areas of compression and rarefaction.
  • A water ripple is a transverse wave. A sound wave in air is a longitudinal wave.

10. What the cork shows

  • The cork moves up and down as the wave passes, but it returns to the same place. The water itself does not travel along with the wave.
  • The wave transfers energy from one place to another, and not water or matter.

11. Measuring the speed of sound

  • Measure the distance from the sound source to the wall with a tape measure.
  • Make a short, loud sound and measure the time for the echo to return with a stopwatch or a data logger.
  • The sound travels to the wall and back, a distance of twice the measured distance. Use v = s / t with this total distance and the measured time.

12. Wave speed

Answer: v=st=248.0=3.0 m/sv = \dfrac{s}{t} = \dfrac{24}{8.0} = 3.0\,\text{m/s}.

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