GCSE Physics (9-1)

1.1 Energy stores and transfers — Practise

Work through these on your own. Keep your working neat: the method matters as much as the answer.

Both the questions and the answers below come from a set that is checked by computer every time the book is built.

  1. A pupil of mass 45 kg climbs to the top of a 6.0 m climbing wall. Take g=9.8 N/kgg = 9.8\,\text{N/kg}. Calculate the energy gained by the gravitational potential store.
  2. A ball of mass 0.25 kg is thrown at 12 m/s. Calculate the energy in its kinetic store.
  3. A spring with spring constant 150 N/m is stretched by 0.12 m. Calculate the energy stored in the elastic potential store.
  4. A 2.0 kg block of aluminium is heated from 15 °C to 65 °C. The specific heat capacity of aluminium is 900 J/kg°C. Calculate the energy transferred to the block.
  5. A pump transfers 36000 J of energy in 20 s. Calculate its power.
  6. A microwave oven has a power of 1200 W and runs for 90 s. Calculate the energy transferred.
  7. A force of 180 N moves a trolley 4.5 m along the line of the force. Calculate the work done.
  8. A car of mass 900 kg slows from 15 m/s to rest. Calculate the energy transferred to the thermal store of the brakes.
  9. A kettle transfers 5.0×105 J5.0 \times 10^5\,\text{J} of energy in 200 s. Calculate its power.
  10. In the chapter problem, 30 kg of water falls 12 m to the wheel each second. Take g=9.8 N/kgg = 9.8\,\text{N/kg}. Calculate the energy the water gives up from its gravitational potential store each second.
  11. A cyclist freewheels down a hill and speeds up. Name the store that decreases and the store that increases.
  12. A box is pushed across a rough floor and slows down until it stops. Describe the energy transfer, naming both stores.
Answers and concise solutions

1. Energy gained by the gravitational potential store

Answer: Ep=mgh=45×9.8×6.0=2646 JE_p = mgh = 45 \times 9.8 \times 6.0 = 2646\,\text{J}, so 2600 J2600\,\text{J} to 2 significant figures.

2. Energy in the kinetic store

Answer: Ek=12mv2=0.5×0.25×122=18 JE_k = \tfrac{1}{2}mv^2 = 0.5 \times 0.25 \times 12^2 = 18\,\text{J}.

3. Energy in the elastic potential store

Answer: Ee=12ke2=0.5×150×0.122=1.08 JE_e = \tfrac{1}{2}ke^2 = 0.5 \times 150 \times 0.12^2 = 1.08\,\text{J}, so 1.1 J1.1\,\text{J} to 2 significant figures.

4. Energy transferred to the block

Answer: ΔE=mcΔθ=2.0×900×50=90000 J\Delta E = mc\Delta\theta = 2.0 \times 900 \times 50 = 90000\,\text{J}, so 9.0×104 J9.0 \times 10^4\,\text{J} to 2 significant figures.

5. Power of the pump

Answer: P=Et=3600020=1800 WP = \dfrac{E}{t} = \dfrac{36000}{20} = 1800\,\text{W}. The trailing zeros in 1800 are not significant here: the answer is quoted to 2 significant figures.

6. Energy transferred by the microwave

Answer: E=Pt=1200×90=108000 JE = Pt = 1200 \times 90 = 108000\,\text{J}, so 1.1×105 J1.1 \times 10^5\,\text{J} to 2 significant figures.

7. Work done on the trolley

Answer: W=Fs=180×4.5=810 JW = Fs = 180 \times 4.5 = 810\,\text{J}.

8. Energy transferred to the brakes

Answer: Ek=12mv2=0.5×900×152=101250 JE_k = \tfrac{1}{2}mv^2 = 0.5 \times 900 \times 15^2 = 101250\,\text{J}, so 1.0×105 J1.0 \times 10^5\,\text{J} to 2 significant figures.

9. Power of the kettle

Answer: P=Et=500000200=2500 WP = \dfrac{E}{t} = \dfrac{500000}{200} = 2500\,\text{W}, quoted to 2 significant figures.

10. Energy given up each second

Answer: Ep=mgh=30×9.8×12=3528 JE_p = mgh = 30 \times 9.8 \times 12 = 3528\,\text{J} each second, so 3500 J3500\,\text{J} to 2 significant figures.

11. The two stores that change

  • The gravitational potential store decreases, because the cyclist is lower down.
  • The kinetic store increases, because the cyclist speeds up.

12. The energy transfer

  • The kinetic store of the box decreases as the box slows.
  • Friction transfers energy to the thermal store of the floor and the box, which increases.

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