Junior Cycle Mathematics

3.2 Prime numbers and prime factorisation — Practise

Work independently. The questions and answers are shown together at the end.

Give every factorisation in index form, and check each one by multiplying it back out before you move on.

  1. Write down all the prime numbers between 20 and 40.
  2. Show that 91 is not a prime number.
  3. Write 360 as a product of its prime factors. Give your answer in index form.
  4. Write 700 as a product of its prime factors, in index form.
  5. 84=22×3×784=2^2\times3\times7. Use the prime factorisation to find how many factors 84 has.
  6. Write 5775 as a product of prime factors. (Hint: it ends in 5, and its digit sum is 24.)
Answers and concise solutions

1. Write down all the prime numbers between 20 and 40.

Answer: 23,29,3123, 29, 31 and 3737. Each has no factor smaller than itself except 1: 21, 27 and 33 divide by 3, 25 and 35 by 5, 39 by 3, and 22, 24, 26, 28, 30, 32, 34, 36 and 38 are even.

2. Show that 91 is not a prime number.

Answer: 91=7×1391=7\times13, so 91 has a factor other than 1 and itself. It is not prime.

3. Write 360 as a product of its prime factors.

Answer: 360=23×32×5360=2^3\times3^2\times5. Divide out 2 three times, then 3 twice, then 5 once.

4. Write 700 as a product of its prime factors.

Answer: 700=22×52×7700=2^2\times5^2\times7.

5. How many factors does 84 have?

Answer: Twelve. Each factor uses 0, 1 or 2 copies of 2, and 0 or 1 copy of each of 3 and 7 — that is 3×2×2=123\times2\times2=12 combinations, and each gives a different factor.

6. Write 5775 as a product of prime factors.

Answer: 5775=3×52×7×115775=3\times5^2\times7\times11.

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